[chbot] Choc Fish Challenge #5

[Synco Reynders]

I was confused why you'd leave 2 unpaired wire in the first place? Yet
alone trying to find them.
/s

On 5 September 2011 14:11, hamster <hamster at snap.net.nz> wrote:
> Humm - very cunning.
>
>> identify the unpaired wires with a lamp that illuminates
>
> That will take on average over 4800 tests.... maybe an hour?
>
> I would be interested in knowing is the quickest way assuming that each
> test takes a second, and a 1km walk takes 10 minutes...
>
> Mike
>
>
> On Mon, 05 Sep 2011 13:59:38 +1200, m.beckett at amuri.net wrote:
>> gUYS
>> Sorry hit some key combination and it went not even close to finished.
>>
>> Our solution is (2km) :-
>>
>> At the start end, hook up the battery to two wires,
>> Pair/join the remaining wires so you end up with 59 pairs and two
>> singles.
>>
>> Travel to the other end (1km) and identify the unpaired wires with a
>> lamp that illuminates.
>> Label one end of the single combination as 1B and connect this to a
>> wire, label this as 2A, then find the other pair, label as 2B.
>> Join 2B onto another wire, label as 3A, find the other pair and label
>> as 3B....etc until 60B.
>>
>> Travel to the start (2km) and connect the lamp to either the positive
>> or negative and try all the pairs.
>> If you get the lamp to light, you can identify the battery end as 1A,
>> the other battery connection as 1B.
>>
>> Connect one end of the lamp to the 1A wire, and break one pair.
>> See how many pairs still light the the lamp, add 2 to this and you have
>> identified the A leg of the pair, with the other of the pair being B
>> leg.
>>
>> If you work through the pairs, you will identify all 60 Pairs, with
>> only 2km.
>>
>>
>> Cheers
>> Mark
>>
>>
>
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