[chbot] !!!!!!!! Choc fish challenge 2 !!!!!!!!!

[Andre Renaud]

Hi Charles,

On 01/08/11 14:13, Charles Manning wrote:
> Under what conditions does the following compile and what will happen when it 
> executes?
> 
>   while(x[j] == j[x]){
> 	j++; x++;
>   }

As far as I can tell, one of x or j has to be an ordinal/integer type.
The other has to be some kind of array type. Since array indexing
essentially becomes addition, x[j] is equivalent to j[x]. I think this
means that it'll run forever.

However, I'm not entirely convinced that typing of x[j] vs j[x] doesn't
come into it, especially if the one of them that is an array has
sizeof() > 1.

Regards,
Andre